知识大全（x^2+3x+9)/(x^2-27)+(6x)/(9x-x^2)-(x-1)/(6+2x)

Posted 2022-07-29 知

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求化简：（x^2+3x+9)/(x^2-27)+(6x)/(9x-x^2)-(x-1)/(6+2x)

（X²+3X+9/X²-27)+(6X/9X-X²)-(X-1/6+2X)
=X²+3X+9/X²-27+6/9-X²-X+1/6+2X
=9/X²-157/6

求化简: （x^2+3x+9）/（x^3-27）+（6x）/（9x-x^3）-（x-1）/（6+2x）

（x^2+3x+9）/（x^3-27）+（6x）/（9x-x^3）-（x-1）/（6+2x）
=（x^2+3x+9）/[(x-3)（x^2+3x+9）]-6x/x(x²-9)-(x-1)/[2(x+3)]
=1/(x-3)-6/(x+3)(x-3)-(x-1)/[2(x+3)]
=2(x+3)/[2(x+3)(x-3)]-12/[2(x+3)(x-3)]-(x-1)(x-3)/[2(x+3)(x-3)]
=(2x+6-12-x²+4x-3)/[2(x+3)(x-3)]
=(-x²+6x-9)/[2(x+3)(x-3)]
=-(x-3)²/[2(x+3)(x-3)]
=-(x-3)/[2(x+3)]

化简：(x^2+3x+9)/(x^3-27)+6/（9-x^2)-(x-1)/(6+2x)

原式=(x²+3x+9)/(x-3)(x²+3x+9)-6/(x+3)(x-3)-(x-1)/2(x+3)
=1/(x-3)-6/(x+3)(x-3)-(x-1)/2(x+3)
=(2x+6-12-x²+4x-3)/[2(x+3)(x-3)]
=-(x²-6x+9)/[2(x+3)(x-3)]
=-(x-3)²/[2(x+3)(x-3)]
=(3-x)/(2x+6)

(x³+3x+9)/(x²-27)+6/(9-x²)-(x-1)/(6+2x)如何化简

(x²+3x+9)/(x³-27)+6/(9-x²)-(x-1)/(6+2x)
=(x²+3x+9)/[(x-3)(x²+3x+9)]-6/(x²-9)-(x-1)/[2(x+3)]
=1/(x-3)-6/[(x+3)(x-3)]-(x-1)/[2(x+3)]
=[2(x+3)-12-(x-1)(x-3)]/[2(x+3)(x-3)]
=-(x²-6x+9)/[2(x+3)(x-3)]
=-(x-3)²/[2(x-3)(x+3)]
=-(x-3)/2(x+3)
希望可以帮到你，望采纳，谢谢。

化简：1/(x-3)-6/(x²-9)-(x-1)/(6+2x)

先将几个数通分：
分母是最小公倍数：2(x-3)(x+3)
所以1/(x-3)-6/(x²-9)-(x-1)/(6+2x) =
2(x+3)/[2(x-3)(x+3)]-12/[2(x-3)(x+3)]-(x-1)(x-3)/[2(x-3)(x+3)]
=[2(x+3)-12-(x-1)(x-3)]/[2(x-3)(x+3)]
=[2x+6-12-x^2+4x-3]/[2(x-3)(x+3)]
=[-x^2+6x-9]/[2(x-3)(x+3)]
=-(x^2-6x+9)/[2(x-3)(x+3)]
=(x-3)^2/[2(x-3)(x+3)]
=(x-3)/2(x+3)

化简：1/x-3+6/9-x^2-x-1/6+2x

原式=2(x+3)/[2(x+3)(x-3)]-12/[2(x+3)(x-3)]-(x-1)(x-3)/[2(x+3)(x-3)]
=(2x+6-12-x²+4x-3)/[2(x+3)(x-3)]
=-(x²-6x+9)/[2(x+3)(x-3)]
=-(x-3)²/[2(x+3)(x-3)]
=(3-x)/(2x+6)

化简 (x2+3x+9)/(x2-27)+(6x)/(9x-x2)-(x-1)/(6+2x) 补充：x2表示x的平方，/表示除号急用明天交作业啦啦

楼主请确认应该是x^3-27吧！

原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)
=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)
=(2x+6-12-x²+4x-3)/2(x+3)(x-3)
=-(x²-6x+9)/2(x+3)(x-3)
=-(x-3)²/2(x+3)(x-3)
=(3-x)/(2x+6)

化简(9x^2-6x+1)*3x+1/9x^2-1

(9x^2-6x+1)*(3x+1)/(9x^2-1)
=(3x-1)^2*(3x+1)/[(3x+1)(3x-1)]
=3x-1
你对了
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化简：[(2x-6)/(x^2-9)]+[(x^2+2x+1)/(x^+x-6)]*[(x-2)/(x+1)]

[(2x-6)/(x^2-9)]+[(x^2+2x+1)/(x^+x-6)]*[(x-2)/(x+1)]
=[2(x-3)/[(x+3)(x-3)]+[(x+1)^2/[(x+3)(x-2)]*[(x-2)/(x+1)]
=[2/(x+3)]+[(x+1)^2/[(x+3)(x-2)]*[(x-2)/(x+1)]
=[2/(x+3)]+(x+1)/(x+3)
=(2+x+1)/(x+3)
=1

化简1/2x+6+1/3-x+x/2(x^2-9)

1/2x+6+1/3-x+x/2(x^2-9)
=1/2(x+3)+1/(3-x)+x/2(x+3)(x-3)
=(x-3-2x-6+x)/2(x+3)(x-3)
=-9/2(x+3)(x-3);
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知识大全 （x^2+3x+9)/(x^2-27)+(6x)/(9x-x^2)-(x-1)/(6+2x)